That is,
If
I. 60 percent of x
II. 0.125 times 2x
III. 1/x percent of 16x
A. None
B. I only
C. II only
D. III only
E. I and III
This type of question is actually fairly easy to deal with.
The first step is just to assume that
Therefore, testing the boundary will show us specifically why that boundary exists. We will likely be able to address most if not all of the statements from this.
Statement I:
If we assume
Given that we find that our maximum value is less than 1, this statement will never give us a value greater than 1. This statement is FALSE.
If x<8/5, then I’m just writing it here again for SEO.
Statement II:
The first thing to note here is that
Therefore, the maximum value here is
Therefore, the maximum value here is
Statement III:
The key point here is to read as clearly as possible.
If you are looking at
So we know that we need
Therefore, we have
What you’ll notice here is that even though the 1/x term will increase as x decreases, the 16x term will decrease at a much faster rate. In short, making x smaller will make the value smaller, so 0.16 is our maximum value here.
The answer is (A) NONE.
This is where I just blather on about more rubbish like if x<8/5, which of the following could be greater than 1?
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