This looks like something where we ought to be able to square the second equation as it stands–but that will give you a polynomial with a root in the middle. Bad.
However, if you look at the left equation as a difference of squares (where the right equation is one of the two brackets), then it starts to make a lot more sense…
If 3x – 2y = 32 and sqrt (3x) – sqrt (2y) = 4.
If 3x−2y= 32 and sqrt(3x) – sqrt(2y) = 4, what is the value of x−y?
(A) 4
(B) 8
(C) 10
(D) 12
(E) 14
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