If 3x – 2y = 32 and sqrt (3x) – sqrt (2y) = 4 GMAT

This looks like something where we ought to be able to square the second equation as it stands–but that will give you a polynomial with a root in the middle. Bad.

However, if you look at the left equation as a difference of squares (where the right equation is one of the two brackets), then it starts to make a lot more sense…

If 3x – 2y = 32 and sqrt (3x) – sqrt (2y) = 4.

If 3x−2y= 32 and sqrt(3x) – sqrt(2y) = 4, what is the value of x−y?

(A) 4
(B) 8
(C) 10
(D) 12
(E) 14

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