In this case, you need to look at the units as mpg/lbs or mpg/mph, then multiply these values by lbs or mph, respectively. It’s awkward, but slow down the video to see more.
Solomon’s truck gets 24 mpg (miles per gallon) when driven at a speed of 40 mph (miles per hour) with no load. His truck’s gas mileage decreases 1 mpg for each 500 pounds of added load and it decreases 1/2 mpg for each 10 mph of increased speed over 40 mph. Which of the following is a formula for the gas mileage of Solomon’s truck when its speed is S mph (S greater than or equal to 40) and it has a load of L pounds?
A. 24−L/500−S/2
B. 24−L/500−S/20
C. 26−L/500−S/20
D. 44−L/500−S/2
E. 44−L/500−S/20
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