I. 24
II. 36
III. 45
(A) I only
(B) II only
(C) I and II only
(D) II and III only
(E) I, II and III
What we need to concern ourselves here is the meaning of the factors within 18 and 60 themselves.
In short, we need to find the Least Common Multiple (LCM) of 18 and 60 and then test each of the statement numbers (24, 36, and 45) to see whether they also fit into this LCM.
This isn’t particularly hard to do, so I’ll take it for granted that you can figure that part out.
The prime factorization of 18 is
The prime factorization of 60 is
That means that, if If x is a multiple of 18 and 60, the Least Common Multiple of these numbers (the smallest number divisible by each one) would be, effectively, the taking the highest power of each of the three present bases.
That is, the
Therefore, the smallest number that would divide by both 18 and 60 can be defined as
This tracks, of course, if you think about it: 90 is a multiple of 18 but not of 60 because it doesn’t have two 2s in it. Therefore, 180 must be the smallest multiple that has the two 2s that are present in 60.
So if 18
If x is a multiple of 18 and 60, I’m just saying this for SEO–bear with me.
Statement I:
The prime factorization of 24 is
That is,
This statement doesn’t work.
Statement II:
The prime factorization of 36 is
Statement III:
The prime factorization of 45 is
And of course if If x is a multiple of 18 and 60, the answer is definitely (D) II and III only.
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